(n^2-n-20)/2=45

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Solution for (n^2-n-20)/2=45 equation: 


n in (-oo:+oo)

(n^2-n-20)/2 = 45 // - 45

(n^2-n-20)/2-45 = 0

(n^2-n-20)/2+(-45*2)/2 = 0

n^2-n-45*2-20 = 0

n^2-n-110 = 0

n^2-n-110 = 0

n^2-n-110 = 0

DELTA = (-1)^2-(-110*1*4)

DELTA = 441

DELTA > 0

n = (441^(1/2)+1)/(1*2) or n = (1-441^(1/2))/(1*2)

n = 11 or n = -10

(n+10)*(n-11) = 0

((n+10)*(n-11))/2 = 0

((n+10)*(n-11))/2 = 0 // * 2

(n+10)*(n-11) = 0

( n+10 )

n+10 = 0 // - 10

n = -10

( n-11 )

n-11 = 0 // + 11

n = 11

n in { -10, 11 }

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